Transition State Theory

Derivation of Vibrational Partition Function qv

To show

(A12)

Again we solve the wave equation for two molecules undergoing oscillation about an equilibrium position x = 0. The potential energy is shown below as a function of the displacement from the equilibrium position x = 017

The uncertainty principle says that we cannot know exactly where the particle is located. Therefore zero frequency of vibration in the ground state, i.e. ν = 0 is not an option18. When ν0 is the frequency of vibration, the ground state energy is

  (V1)

Harmonic oscillator 19    
Spring Force potential energy from equilibrium position x = 0    
   
the solution is of the form for t=0 then x=0    
   
where    
   
   
The potential energy is    
  (V2)
We now want to show    
  (V3)
We now solve the wave equation:    
  (V4)
to find the allowable energies, ε.    
Let , , where , , and    
With these changes of variables Eqn. (A15) becomes    
  (V5)
The solutions to this equation20 will go to infinity unless    
ε = 2ν +1
   
ν = 0, 1, 2, 3 . . .
   
[c = speed of light]21  
   
λ = wave length
   
  (V6)
Measuring energy relative to the zero point vibration frequency, (i.e., ν = 0) gives    
   
Substituting for in the partition function summation    
   
   

This is the result we have been looking for!

  (V7)
For , we can make the approximation    
  (V8)
For m multiple frequencies of vibration    
   
Order of Magnitude and Representative Values    
For H2O  we have three vibrational frequencies with corresponding wave numbers, .    
   
   
and    
   
   

17P. W. Atkins, Physical Chemistry, 5th ed. (New York: Freeman, 1994), p. 402.

18 P. W. Atkins, Physical Chemistry, 5th ed. (New York: Freeman, 1994), pp. 22, 402.

19P. W. Atkins, Physical Chemistry, 5th ed. (New York: Freeman, 1994), p. 402.

20P. W. Atkins, Physical Chemistry, 5th ed. (New York: Freeman, 1994), p. 22, Appendix 8.

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