Chapter 4 Example

Writing -r_A Solely as a Function of X. 

Write the rate law for the elementary liquid phase reaction

solely in terms of conversion. The feed to the batch reactor is equal molar A and B with C_A0 = 2 mol/dm³ and k_A= .01 (dm³/mol)⁴1/s.

Hint 1: What is the rate law?

Hint 2: What is the concentration of A?

Hint 3: What is the concentration of B?

Full Solution

        What is the rate law?

        The reaction is elementary so what happens to the coefficients from the reaction?

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        What is the concentration of A?

        Liquid phase, v = v_o (no volume change)

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Hint 3

What is the concentration of B?

What is Θ_B?

Equal molar

Species A is the limiting reactant because the feed is equal molar in A and B, and two moles of B consumes 3 moles of A.

Back to Problem

Write the rate law for the elementary liquid phase reaction

solely in terms of conversion. The feed to the batch reactor is equal molar A and B with C_A0 = 2 mol/dm³ and k_A= .01 (dm³/mol)⁴1/s.

1) Rate Law: -r_A=kC³_AC²_B

2) Stoichiometry:

Species A

Liquid phase, v = v_o (no volume change)

Species B

What is Θ_B?

Species A is the limiting reactant because the feed is equal molar in A and B, and two moles of B consumes 3 moles of A.

We now have -r_A=f(X) and can size reactors or determine batch reaction times.

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