Example 12-1 Isomerization of Normal Butane with Heat Exchanger |POLVER05_0 |1 Cpc =28 m = 500 d(Ta) / d(V) = Ua*(T-Ta)/m/Cpc Ua = 5000 Ta(0) = 310 d(X)/d(V) = -ra/Fa0 # d(T)/d(V) = ((ra*deltaH)-Ua*(T-Ta))/Cpo/Fa0 # Ca0 = 9.3 # Fa0 = .9*163*.1 # Kc = 3.03*exp(-830.3*((T-333)/(T*333))) # k = 31.1*exp(7906*(T-360)/(T*360)) # Xe = Kc/(1+Kc) # ra = -k*Ca0*(1-(1+1/Kc)*X) # deltaH = -6900 # Cpo = 159 # rate = -ra # V(0)=0 X(0)=0 T(0)=305 V(f)=5