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Heterogeneous Examples

We start with the catalyst design equation derived in the Type 1 Home Problem solution :


Dividing both sides by the catalyst bulk density gives the conversion with respect to volume:


Volume is the cross sectional area times the length:


Taking the derivative of the volume gives:


In our case the cross sectional area of the reactor stays constant. This reduces the previous equation to


Substituting into the design equation:


The rest of the equations needed are the same as in the Type 1 Home Problem solution.

Back to problem statement Part 2 of solution


CRE > Thoughts > Ten Types > Heterogeneous Example 5