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Heterogeneous Examples

The solution to the first PFR is the same as the Type 1 Home Problem solution.

In the second problem the only assumption that can be made is that the problem is isothermal. The volumeteric flowrate then becomes


This causes the rate law to be


To solve this problem, we can plug in our know values and equations into POLYMATH to solve:

y = P/Po



Graph of Conversion and y vs. Catalyst Weight

X = 0.907

y = 0.072

0.072 = P/Po

P = 0.072 Po

P = 0.72 atm

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CRE > Thoughts > Ten Types > Heterogeneous Example 8