LEADING QUESTIONS
13-epi-6 and 21 - were formed in this reaction. Provide a detailed mechanism:
The reaction follows the same mechanism as that which produces Compound 6 until step 7: The backside attack of the chloride ion pushes SO3Cl through an eclipsed conformation, so this would not be a major product.
The formation of the other minor product is as follows:
The high electronegativity of chlorine makes this product unlikely to form. Chlorine is more likely to stay bound to the sulfur atom of SO3HCl.
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